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Mathlib.Combinatorics.Enumerative.DyckWord

Dyck words #

A Dyck word is a sequence consisting of an equal number n of symbols of two types such that for all prefixes one symbol occurs at least as many times as the other. If the symbols are ( and ) the latter restriction is equivalent to balanced brackets; if they are U = (1, 1) and D = (1, -1) the sequence is a lattice path from (0, 0) to (0, 2n) and the restriction requires the path to never go below the x-axis.

This file defines Dyck words and constructs their bijection with rooted binary trees, one consequence being that the number of Dyck words with length 2 * n is catalan n.

Main definitions #

Main results #

Implementation notes #

While any two-valued type could have been used for DyckStep, a new enumerated type is used here to emphasise that the definition of a Dyck word does not depend on that underlying type.

inductive DyckStep :

A DyckStep is either U or D, corresponding to ( and ) respectively.

Equations
theorem DyckStep.dichotomy (s : DyckStep) :
s = U s = D

Named in analogy to Bool.dichotomy.

structure DyckWord :

A Dyck word is a list of DyckSteps with as many Us as Ds and with every prefix having at least as many Us as Ds.

theorem DyckWord.ext {x y : DyckWord} (toList : x = y) :
x = y
theorem DyckWord.ext_iff {x y : DyckWord} :
x = y x = y
Equations
Equations

Dyck words form an additive cancellative monoid under concatenation, with the empty word as 0.

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  • One or more equations did not get rendered due to their size.
theorem DyckWord.toList_eq_nil {p : DyckWord} :
p = [] p = 0

The only Dyck word that is an additive unit is the empty word.

Equations
theorem DyckWord.head_eq_U (p : DyckWord) (h : p []) :
(↑p).head h = DyckStep.U

The first element of a nonempty Dyck word is U.

theorem DyckWord.getLast_eq_D (p : DyckWord) (h : p []) :

The last element of a nonempty Dyck word is D.

Prefix of a Dyck word as a Dyck word, given that the count of Us and Ds in it are equal.

Equations
  • p.take i hi = { toList := List.take i p, count_U_eq_count_D := hi, count_D_le_count_U := }

Suffix of a Dyck word as a Dyck word, given that the count of Us and Ds in the prefix are equal.

Equations
  • p.drop i hi = { toList := List.drop i p, count_U_eq_count_D := , count_D_le_count_U := }

Nest p in one pair of brackets, i.e. x becomes (x).

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@[simp]

A property stating that p is nonempty and strictly positive in its interior, i.e. is of the form (x) with x a Dyck word.

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Denest p, i.e. (x) becomes x, given that p.IsNested.

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theorem DyckWord.nest_denest (p : DyckWord) (hn : p.IsNested) :
(p.denest hn).nest = p

The semilength of a Dyck word is half of the number of DyckSteps in it, or equivalently its number of Us.

Equations

p.firstReturn is 0 if p = 0 and the index of the D matching the initial U otherwise.

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The left part of the Dyck word decomposition, inside the U, D pair that firstReturn refers to. insidePart 0 = 0.

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The right part of the Dyck word decomposition, outside the U, D pair that firstReturn refers to. outsidePart 0 = 0.

Equations
@[simp]
theorem DyckWord.insidePart_add {p q : DyckWord} (h : p 0) :
@[simp]
theorem DyckWord.outsidePart_add {p q : DyckWord} (h : p 0) :
Equations
  • One or more equations did not get rendered due to their size.
@[irreducible]
theorem DyckWord.le_add_self (p q : DyckWord) :
q p + q
theorem DyckWord.infix_of_le {p q : DyckWord} (h : p q) :
p <:+: q
theorem DyckWord.le_of_suffix {p q : DyckWord} (h : p <:+ q) :
p q

Partial order on Dyck words: p ≤ q if a (possibly empty) sequence of insidePart and outsidePart operations can turn q into p.

Equations

Equivalence between Dyck words and rooted binary trees.

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Equivalence between Dyck words of semilength n and rooted binary trees with n internal nodes.

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  • One or more equations did not get rendered due to their size.

There are catalan n Dyck words of semilength n (or length 2 * n).

Extension for the positivity tactic: p.firstReturn is positive if p is nonzero.